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14x^2-12x=135
We move all terms to the left:
14x^2-12x-(135)=0
a = 14; b = -12; c = -135;
Δ = b2-4ac
Δ = -122-4·14·(-135)
Δ = 7704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7704}=\sqrt{36*214}=\sqrt{36}*\sqrt{214}=6\sqrt{214}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{214}}{2*14}=\frac{12-6\sqrt{214}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{214}}{2*14}=\frac{12+6\sqrt{214}}{28} $
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